
Let f(x) = x^3 − 3x^2 + 2x. For which x does f have critical points (where f'(x) = 0)?
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Get StartedLet f(x) = x^3 − 3x^2 + 2x. For which x does f have critical points (where f'(x) = 0)?
Options:
- x = (3 ± √3)/3 (approximately 0.42265 and 1.57735)
- x = 0 and x = 2
- x = −1 and x = 3
- No real critical points
Correct answer: x = (3 ± √3)/3 (approximately 0.42265 and 1.57735)
Explanation: f'(x)=3x^2−6x+2, whose discriminant is 12, giving roots x=(3±√3)/3 ≈ 0.42265 and 1.57735; the discriminant 12 yields 2√3 as the radical.
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