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For the quadratic f(x) = 2x^2 − 8x + 6, what are the coor... | QuestionStock

Representative image for question: For the quadratic f(x) = 2x^2 − 8x + 6, what are the coordinates of its vertex?

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For the quadratic f(x) = 2x^2 − 8x + 6, what are the coordinates of its vertex?

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For the quadratic f(x) = 2x^2 − 8x + 6, what are the coordinates of its vertex?

Options:

(2, −2)
(−2, 2)
(1, −4)
(0, 6)

Correct answer: (2, −2)

Explanation: Vertex x-coordinate is −b/(2a) = 8/(4) = 2, and f(2)=2·4−16+6 = −2, so the vertex is (2, −2). The calculation uses the concrete value −b/(2a)=2.

Created 2026-03-10T18:04:24.160Z. Updated 2026-03-10T18:04:24.160Z.